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JEE Main 2024 (29 Jan, Shift 1) · Reflection & Mirrors

Reflection & Mirrors question from JEE Main 2024 (29 Jan, Shift 1)

Q17JEE Main 2024 · 29 JAN · SHIFT 1Easy

Reflection & Mirrors

A convex mirror of radius of curvature 30 cm30\text{ cm} forms an image that is half the size of the object. The object distance is:

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Answer: (b)

  1. Convex mirror: f=+R2=+15 cmf = +\frac{R}{2} = +15\text{ cm}; image is virtual and erect, m=+12m = +\frac{1}{2}.
  2. m=−vu=12⇒v=−u2m = -\frac{v}{u} = \frac{1}{2} \Rightarrow v = -\frac{u}{2}
  3. 1v+1u=1f: −2u+1u=−1u=115\frac{1}{v} + \frac{1}{u} = \frac{1}{f}: \ -\frac{2}{u} + \frac{1}{u} = -\frac{1}{u} = \frac{1}{15}
  4. u=−15 cmu = -15\text{ cm}, so the answer is (b) −15-15 cm.
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