A conveyor belt is moving with constant velocity (V). Sand is being dropped on the belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity V m/s will be (a) MV/2 N (b) 2 MV N (c) Zero N (d) MV N

Answer: (d). Sand falling on the belt must be given horizontal speed V, so momentum is added at rate dp/dt = Vdm/dt. F = V · M = MV So the answer is (d) MV N.

A conveyor belt is moving with constant velocity (V). Sand is being… | MHT CET 2025 (21 Apr, Shift 2)

Q6MHT CET 2025 · 21 APR · SHIFT 2Easy

Impulse & Momentum Conservation

A conveyor belt is moving with constant velocity (V). Sand is being dropped on the belt at the rate of $M\text{ kg/s}$ . The force necessary to keep the belt moving with a constant velocity $V\text{ m/s}$ will be

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Answer: (d)

Sand falling on the belt must be given horizontal speed $V$ , so momentum is added at rate $\frac{dp}{dt} = V\frac{dm}{dt}$ .
$F = V \cdot M = MV$
So the answer is (d) $MV$ N.

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Impulse & Momentum Conservation question from MHT CET 2025 (21 Apr, Shift 2)

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