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JEE Main 2022 (25 Jun, Shift 2) · Calorimetry, Latent Heat & Mechanical Equivalent of Heat

Calorimetry, Latent Heat & Mechanical Equivalent of Heat question from JEE Main 2022 (25 Jun, Shift 2)

Q25JEE Main 2022 · 25 JUN · SHIFT 2Medium

Calorimetry, Latent Heat & Mechanical Equivalent of Heat

A copper block of mass 5.0 kg is heated to a temperature of 500∘^{\circ}C and is placed on a large ice block. What is the maximum amount of ice that can melt? [Specific heat of copper: 0.39 J g−^{-}1 ∘C−^{\circ}\text{C}^{-}1 and latent heat of fusion of water: 335 J g−^{-}1]

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Answer: (c)

  1. Copper cools from 500∘C500^{\circ}\text{C} to 0∘C0^{\circ}\text{C}: Q=5000×0.39×500=9.75×105 JQ = 5000 \times 0.39 \times 500 = 9.75 \times 10^5\text{ J}
  2. Ice melted =9.75×105335≈2910 g= \dfrac{9.75 \times 10^5}{335} \approx 2910\text{ g}
  3. So the answer is (c) 2.9 kg2.9\text{ kg}.
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