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JEE Main 2019 (11 Jan, Shift 2) · Self-Inductance & Energy

Self-Inductance & Energy question from JEE Main 2019 (11 Jan, Shift 2)

Q75JEE Main 2019 · 11 JAN · SHIFT 2Medium

Self-Inductance & Energy

A copper wire is wound on a wooden frame, whose shape is that of an equilateral triangle. If the linear dimension of each side of the frame is increased by a factor of 3, keeping the number of turns of the coil per unit length of the frame the same, then the self inductance of the coil:

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Answer: (d)

  1. The wire is wound around the bars of the frame, like a solenoid bent along the triangle: L=μ0n2A lL = \mu_0 n^2 A\, l.
  2. Here AA is the cross-section of the frame bar (unchanged) and ll is the total wound length (perimeter).
  3. With nn fixed, L∝lL \propto l; each side ×3\times 3 gives l×3l \times 3.
  4. So the answer is (d) increases by a factor of 3.
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