A cricket player catches a ball of mass 120 g moving with 25 m/s speed. If the catching process is completed in 0.1 s then the magnitude of force exerted by the ball on the hand of player will be (in SI unit): (a) 30 (b) 24 (c) 12 (d) 25

Answer: (a). F = (Δ p)/(Δ t) = mv/t (the ball comes to rest). F = (0.12 × 25)/(0.1) = 30 N So the answer is (a) 30.

A cricket player catches a ball of mass 120 g moving with 25 m/s… | JEE Main 2024 (1 Feb, Shift 2)

Q10JEE Main 2024 · 1 FEB · SHIFT 2Easy

Impulse & Momentum Conservation

A cricket player catches a ball of mass $120\text{ g}$ moving with $25\text{ m/s}$ speed. If the catching process is completed in $0.1\text{ s}$ then the magnitude of force exerted by the ball on the hand of player will be (in SI unit):

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Answer: (a)

$F = \frac{\Delta p}{\Delta t} = \frac{mv}{t}$ (the ball comes to rest).
$F = \frac{0.12 \times 25}{0.1} = 30\text{ N}$
So the answer is (a) 30.

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