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JEE Main 2024 (8 Apr, Shift 2) · Archimedes' Principle & Floatation

Archimedes' Principle & Floatation question from JEE Main 2024 (8 Apr, Shift 2)

Q9JEE Main 2024 · 8 APR · SHIFT 2Medium

Archimedes' Principle & Floatation

A cube of ice floats partly in water and partly in kerosene oil. The ratio of volume of ice immersed in water to that in kerosene oil (specific gravity of Kerosene oil = 0.8, specific gravity of ice = 0.9):

Figure

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Answer: (d)

  1. Let VwV_w, VkV_k be the volumes in water and kerosene, V=Vw+VkV = V_w + V_k.
  2. Weight = upthrust: 0.9 V=1⋅Vw+0.8 Vk0.9\,V = 1 \cdot V_w + 0.8\,V_k
  3. 0.9(Vw+Vk)=Vw+0.8Vk⇒0.1Vk=0.1Vw0.9(V_w + V_k) = V_w + 0.8 V_k \Rightarrow 0.1 V_k = 0.1 V_w
  4. Vw:Vk=1:1V_w : V_k = 1 : 1, so the answer is (d).
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