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JEE Main 2026 (24 Jan, Shift 2) · Archimedes' Principle & Floatation

Archimedes' Principle & Floatation question from JEE Main 2026 (24 Jan, Shift 2)

Q3JEE Main 2026 · 24 JAN · SHIFT 2Easy

Archimedes' Principle & Floatation

A cubical block of density ρb=600 kg/m3\rho_b = 600\text{ kg/m}^{3} floats in a liquid of density ρe=900 kg/m3\rho_{\text{e}} = 900\text{ kg/m}^{3}. If the height of block is H=8.0 cmH = 8.0\text{ cm} then height of the submerged part is

______ cm.

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Answer: (d)

  1. Floating: ρbAHg=ρeAhg⇒h=ρbρeH\rho_b A H g = \rho_e A h g \Rightarrow h = \dfrac{\rho_b}{\rho_e} H
  2. h=600900×8.0=5.33h = \dfrac{600}{900} \times 8.0 = 5.33 cm
  3. So the answer is (d) 5.3 cm.
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