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JEE Main 2019 (10 Apr, Shift 2) · Archimedes' Principle & Floatation

Archimedes' Principle & Floatation question from JEE Main 2019 (10 Apr, Shift 2)

Q18JEE Main 2019 · 10 APR · SHIFT 2Medium

Archimedes' Principle & Floatation

A cubical block of side 0.5 m floats on water with 30% of its volume under water. What is the maximum weight that can be put on the block without fully submerging it under water? [Take, density of water = 103 kg/m3]

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Answer: (b)

  1. Volume V=0.53=0.125V = 0.5^3 = 0.125 m3^{3}. Block mass = displaced water mass =0.3×0.125×103=37.5= 0.3 \times 0.125 \times 10^{3} = 37.5 kg.
  2. Fully submerged, upthrust supports 0.125×103=1250.125 \times 10^{3} = 125 kg.
  3. Extra load =125−37.5=87.5= 125 - 37.5 = 87.5 kg
  4. So the answer is (b) 87.5 kg.
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