A current carrying circular loop of radius ' R ' and current carrying… | MHT CET 2024 (9 May, Shift 2)

Q34MHT CET 2024 · 9 MAY · SHIFT 2Medium

Magnetic Field of Straight Wires

A current carrying circular loop of radius ' $R$ ' and current carrying long straight wire are placed in the same plane. $I_c$ and $I_w$ are the currents through circular loop and long straight wire respectively. The perpendicular distance between centre of the circular loop and wire is ' d '. The magnetic field at the centre of the loop will be zero when separation ' $d$ ' is equal to

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Answer: (a)

Field of loop at centre $= \frac{\mu_0 I_c}{2R}$ ; field of long wire at distance $d$ $= \frac{\mu_0 I_w}{2\pi d}$ .
For zero net field the two must be equal and opposite: $\frac{\mu_0 I_c}{2R} = \frac{\mu_0 I_w}{2\pi d}$
$d = \frac{R I_w}{\pi I_c}$
So the answer is (a) $\frac{R I_w}{\pi I_c}$ .

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Magnetic Field of Straight Wires question from MHT CET 2024 (9 May, Shift 2)

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