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NEET 2011 (AIPMT, Prelims) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from NEET 2011 (AIPMT, Prelims)

Q62NEET 2011 · AIPMT · PRELIMSMedium

Force on Current-Carrying Conductors

A current carrying closed loop in the form of a right angle isosceles triangle ABC is placed in uniform magnetic field acting along AB. If the magnetic force on the arm BC is $\vec{F},$ the force on the arm AC is

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Answer: (b)

Net magnetic force on a closed current loop in a uniform field is zero.
Arm AB is parallel to $\vec{B}$ , so the force on AB is zero.
$\vec{F}_{AC} + \vec{F}_{BC} = 0 \Rightarrow \vec{F}_{AC} = -\vec{F}$
So the answer is (b) $-\vec{F}$ .

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