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MHT CET 2026 (14 May, Shift 1) · Mutual Inductance

Mutual Inductance question from MHT CET 2026 (14 May, Shift 1)

Q2MHT CET 2026 · 14 MAY · SHIFT 1Easy

Mutual Inductance

A current i=10sin⁡(100πt)i = 10\sin(100\pi t) A is passed in first coil, which induces a maximum e.m.f. 5π5\pi V in second coil. The mutual inductance between the coils is

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Answer: (d)

  1. e=Mdidte = M\dfrac{di}{dt}, so emax⁡=MI0ωe_{\max} = M I_0 \omega.
  2. 5π=M×10×100π⇒M=5×10−35\pi = M \times 10 \times 100\pi \Rightarrow M = 5\times 10^{-3} H
  3. So the answer is (d) 55 mH.
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