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MHT CET 2025 (20 Apr, Shift 2) · Magnetic Field of Straight Wires

Magnetic Field of Straight Wires question from MHT CET 2025 (20 Apr, Shift 2)

Q22MHT CET 2025 · 20 APR · SHIFT 2Medium

Magnetic Field of Straight Wires

A current ' I ' is flowing in a conductor PQRST as shown in figure. The radius of curved path QRS is ' R ' and length of straight portion PQ and ST is very large. The magnetic field at the centre [O][\text{O}] of the curved part is ( μ0=\mu_0 = permeability of free space)

Figure

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Answer: (b)

  1. PQ lies on a line through O: zero field.
  2. Arc QRS is 34\frac{3}{4} of a circle: 34⋅μ0i2r=μ0i4πr⋅3π2\frac{3}{4} \cdot \frac{\mu_0 i}{2r} = \frac{\mu_0 i}{4\pi r} \cdot \frac{3\pi}{2}, anticlockwise, so along +k^+\hat{k}.
  3. ST is semi-infinite starting directly below O: μ0i4πr\frac{\mu_0 i}{4\pi r}, also along +k^+\hat{k}.
  4. B⃗=μ0i4πr(3π2+1)k^\vec{B} = \frac{\mu_0 i}{4\pi r}\left(\frac{3\pi}{2} + 1\right)\hat{k}, so the answer is (b).
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