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NEET 2010 (AIPMT, Mains) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from NEET 2010 (AIPMT, Mains)

Q102NEET 2010 · AIPMT · MAINSMedium

Biot-Savart Law & Circular Coils

A current loop consists of two identical semicircular parts each of radius R, one lying in the x-y plane and the other in x-z plane. If the current in the loop is $i$ . The resultant magnetic field due to the two semicircular parts at their common centre is

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Answer: (a)

Each semicircle gives $\dfrac{\mu_0 i}{4R}$ at the centre.
One lies in the x-y plane (field along z), the other in x-z plane (field along y): the fields are perpendicular.
$B = \sqrt{2}\cdot\dfrac{\mu_0 i}{4R} = \dfrac{\mu_0 i}{2\sqrt{2}R}$
So the answer is (a).

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