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MHT CET 2024 (4 May, Shift 2) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2024 (4 May, Shift 2)

Q35MHT CET 2024 · 4 MAY · SHIFT 2Easy

Self-Inductance & Energy

A current of 0.5 A is passed through winding of a long solenoid having 400 turns. The magnetic flux linked with each turn is $3 \times 10^{-3}\text{ Wb}$ . The self inductance of the solenoid is

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Answer: (a)

$L = \frac{N\phi}{I}$
$L = \frac{400 \times 3\times10^{-3}}{0.5} = \frac{1.2}{0.5}$
$L = 2.4\text{ H}$ , so the answer is (a).

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