Kirchhoff's Laws & Measuring Instruments question from JEE Main 2022 (25 Jul, Shift 2)

Answer: (d)

1. $10\text{ k}\Omega \parallel 5\text{ k}\Omega = \frac{10}{3}\text{ k}\Omega$
2. Between A and B: $5 + \frac{10}{3} + 10 = \frac{55}{3}\text{ k}\Omega$ in series
3. $V_{AB} = 15\text{ mA} \times \frac{55}{3}\text{ k}\Omega = 275\text{ V}$
4. So the answer is (d) 275 V.