A current of 5 A flows in a square loop of side 1 m placed in air. The magnetic field at the centre of the loop is X√(2) × 10⁻⁷ T. The value of X is _________. Numerical answer type. Work it out, then open the answer.

Answer: 40. Square loop of side a: B = (2√(2)μ₀ I)/(π a). B = 2√(2) × 4 × 10⁻⁷ × 5 = 40√(2) × 10⁻⁷ T So X = 40.

A current of 5 A flows in a square loop of side 1 m placed in air… | JEE Main 2024 (30 Jan, Shift 2)

Q36JEE Main 2024 · 30 JAN · SHIFT 2Medium

Magnetic Field of Straight Wires

A current of $5\text{ A}$ flows in a square loop of side $1\text{ m}$ placed in air. The magnetic field at the centre of the loop is $X\sqrt{2} \times 10^{-7}\text{ T}$ . The value of $X$ is _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 40

Square loop of side $a$ : $B = \frac{2\sqrt{2}\mu_0 I}{\pi a}$ .
$B = 2\sqrt{2} \times 4 \times 10^{-7} \times 5 = 40\sqrt{2} \times 10^{-7}$ T
So $X = 40$ .

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