A current of 6A enters one corner P of an equilateral triangle PQR having 3 wires of resistance 2 Ω each and leaves by the corner R. The currents i1 in ampere is _________. Numerical answer type. Work it out, then open the answer.

Answer: 2. From P to R: path PQR ( 2 + 2 = 4 Ω) carries i₁; direct PR ( 2 Ω) carries i₂. Current divides inversely as resistance: i₁ = 6 × (2)/(4 + 2) = 2 A i₁ = 2 A

A current of 6A enters one corner P of an equilateral triangle PQR… | JEE Main 2021 (25 Feb, Shift 2)

Q52JEE Main 2021 · 25 FEB · SHIFT 2Medium

Combination of Resistors

A current of 6A enters one corner P of an equilateral triangle PQR having 3 wires of resistance 2 $\Omega$ each and leaves by the corner R. The currents i1 in ampere is _________.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 2

From P to R: path PQR ( $2 + 2 = 4\ \Omega$ ) carries $i_1$ ; direct PR ( $2\ \Omega$ ) carries $i_2$ .
Current divides inversely as resistance: $i_1 = 6 \times \dfrac{2}{4 + 2} = 2$ A
$i_1 = 2$ A

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