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JEE Main 2021 (24 Feb, Shift 1) · Electric Current, Drift Velocity & Current Density

Electric Current, Drift Velocity & Current Density question from JEE Main 2021 (24 Feb, Shift 1)

Q19JEE Main 2021 · 24 FEB · SHIFT 1Easy

Electric Current, Drift Velocity & Current Density

A current through a wire depends on time as

i = α\alpha0t + β\betat2

where α\alpha0 = 20 A/s and β\beta = 8 As−2{}^{-2}. Find the charge crossed through a section of the wire in 15 s.

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Answer: (d)

  1. Current i=α0t+βt2i = \alpha_0 t + \beta t^{2}
  2. q=∫015i dt=α0t22+βt33q = \int_0^{15} i\,dt = \dfrac{\alpha_0 t^{2}}{2} + \dfrac{\beta t^{3}}{3}
  3. q=20×2252+8×33753=2250+9000q = \dfrac{20 \times 225}{2} + \dfrac{8 \times 3375}{3} = 2250 + 9000
  4. q=11250 Cq = 11250\text{ C}, so the answer is (d).
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