A cyclist starts from the point P of a circular ground of radius 2 km and travels along its circumference to the point S. The displacement of a cyclist is: (a) √(8) km (b) 4 km (c) 6 km (d) 8 km

Answer: (a). Going P → Q → R → S covers 3/4 of the circle, but only the end points matter for displacement. OP ⊥ OS, so PS = √(r² + r²) = r√(2). PS = 2√(2) = √(8) km. So the answer is (a) √(8) km.

A cyclist starts from the point P of a circular ground of radius 2 km… | JEE Main 2024 (4 Apr, Shift 2)

Q15JEE Main 2024 · 4 APR · SHIFT 2Easy

Angular Variables

A cyclist starts from the point $P$ of a circular ground of radius $2\text{ km}$ and travels along its circumference to the point $S$ . The displacement of a cyclist is:

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Answer: (a)

Going $P \to Q \to R \to S$ covers $3/4$ of the circle, but only the end points matter for displacement.
$OP \perp OS$ , so $PS = \sqrt{r^2 + r^2} = r\sqrt{2}$ .
$PS = 2\sqrt{2} = \sqrt{8}$ km.
So the answer is (a) $\sqrt{8}$ km.

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