A cylinder contains water upto a height ' H '. It has three orifices O₁, O₂, O₃ as shown in the figure. Let V₁, V₂, V₃ be the speed of efflux of water from the three orifices. Then (a) V₁ = V₂ = V₃ (b) V₁ V₂ > V₃ (d) V₁ = V₃ > V₂

Answer: (b). Torricelli: v = √(2gh), where h is the depth of the orifice below the free surface. O₁ is shallowest and O₃ deepest, so h₁ < h₂ < h₃. So the answer is (b) V₁ < V₂ < V₃.

A cylinder contains water upto a height ' H '. It has three orifices… | MHT CET 2024 (16 May, Shift 1)

Q9MHT CET 2024 · 16 MAY · SHIFT 1Easy

Velocity of Efflux (Torricelli)

A cylinder contains water upto a height ' $H$ '. It has three orifices $O_1, O_2, O_3$ as shown in the figure. Let $V_1, V_2, V_3$ be the speed of efflux of water from the three orifices. Then

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Answer: (b)

Torricelli: $v = \sqrt{2gh}$ , where $h$ is the depth of the orifice below the free surface.
$O_1$ is shallowest and $O_3$ deepest, so $h_1 < h_2 < h_3$ .
So the answer is (b) $V_1 < V_2 < V_3$ .

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Velocity of Efflux (Torricelli) question from MHT CET 2024 (16 May, Shift 1)

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