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JEE Main 2019 (10 Jan, Shift 2) · Other SHM Systems

Other SHM Systems question from JEE Main 2019 (10 Jan, Shift 2)

Q14JEE Main 2019 · 10 JAN · SHIFT 2Medium

Other SHM Systems

A cylindrical plastic bottle of negligible mass is filled with 310 ml of water and left floating in a pond with still water. If pressed downward slightly and released, it starts performing simple harmonic motion at angular frequency ω\omega. If the radius of the bottle is 2.5 cm then ω\omega is close to – (density of water = 103 kg/m3).

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Answer: (d)

  1. ω=ρAgm\omega = \sqrt{\frac{\rho A g}{m}} with m=0.31 kgm = 0.31\text{ kg}, A=π(0.025)2=1.96×10−3 m2A = \pi(0.025)^2 = 1.96 \times 10^{-3}\text{ m}^2.
  2. ω=103×1.96×10−3×9.80.31=62≈7.9 rad/s\omega = \sqrt{\frac{10^3 \times 1.96 \times 10^{-3} \times 9.8}{0.31}} = \sqrt{62} \approx 7.9\text{ rad/s}
  3. So the answer is (d).
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