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JEE Main 2012 (AIEEE) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from JEE Main 2012 (AIEEE)

Q117JEE Main 2012 · AIEEEEasy

Organ Pipes & Resonance Tube

A cylindrical tube, open at both ends, has a fundamental frequency, $f,$ in air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of the air-column is now:

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Answer: (a)

Open pipe: $f = \frac{v}{2L}$ .
Half in water leaves a closed pipe of length $\frac{L}{2}$ : $f' = \frac{v}{4(L/2)} = \frac{v}{2L}$ .
So the answer is (a) $f$ .

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