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MHT CET 2021 (24 Sep, Shift 2) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2021 (24 Sep, Shift 2)

Q83MHT CET 2021 · 24 SEP · SHIFT 2Easy

Organ Pipes & Resonance Tube

A cylindrical tube open at both ends has fundamental frequency 'n' in air. The tube is dipped vertically in water so that one-fourth of it is in water. The fundamental frequency of the air column becomes

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Answer: (d)

Open pipe: $n = \frac{v}{2L}$ .
One-fourth in water leaves a closed pipe of length $\frac{3L}{4}$ : $n' = \frac{v}{4(3L/4)} = \frac{v}{3L}$ .
$n' = \frac{2}{3}\cdot\frac{v}{2L} = \frac{2n}{3}$
So the answer is (d) $\frac{2n}{3}$ .

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