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NEET 1997 (AIPMT) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from NEET 1997 (AIPMT)

Q120NEET 1997 · AIPMTEasy

Organ Pipes & Resonance Tube

A cylindrical tube, open at both ends has fundamental frequency ff in air. The tube is dipped vertically in water, so that half of it is in water. The fundamental frequency of air column is now

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Answer: (d)

  1. Open pipe: f=v2Lf = \frac{v}{2L}.
  2. Half in water leaves a closed pipe of length L2\frac{L}{2}: f′=v4(L/2)=v2Lf' = \frac{v}{4(L/2)} = \frac{v}{2L}.
  3. So the answer is (d) ff.
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