Velocity of Efflux (Torricelli) question from JEE Main 2026 (6 Apr, Shift 2)

Answer: (b)

1. Height of vessel: $H = \frac{V}{\pi r^2} = \frac{0.528}{\frac{22}{7}(0.4)^2} = 1.05\text{ m} = 105\text{ cm}$
2. Block has the same height, so the water top is 210 cm above the ground; the hole is at $y = 210 - 70 = 140$ cm above ground, depth $h = 70$ cm.
3. Range: $R = 2\sqrt{h\,y} = 2\sqrt{70 \times 140} = 2 \times 70\sqrt{2} = 140\sqrt{2}\text{ cm}$
4. So the answer is (b) $140\sqrt{2}$.