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JEE Main 2014 (9 Apr, Shift 1) · Cells: EMF, Internal Resistance & Combinations

Cells: EMF, Internal Resistance & Combinations question from JEE Main 2014 (9 Apr, Shift 1)

Q40JEE Main 2014 · 9 APR · SHIFT 1Medium

Cells: EMF, Internal Resistance & Combinations

A d.c. main supply of e.m.f. 220 V is connected across a storage battery of e.m.f. 200 V through a resistance of 1 Ω\Omega. The battery terminals are connected to an external resistance 'R'. The minimum value of 'R', so that a current passes through the battery to charge it is:

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Answer: (c)

  1. Battery (200 V) and RR are in parallel, fed by 220 V through 1 Ω1\ \Omega.
  2. At the threshold, battery current is zero and its terminal voltage is 200 V: supply current =220−2001=20 A= \frac{220 - 200}{1} = 20\text{ A}, all through RR.
  3. Charging needs 200R<20⇒R>10 Ω\frac{200}{R} < 20 \Rightarrow R > 10\ \Omega
  4. The smallest option above 10 Ω10\ \Omega is 11 Ω11\ \Omega. So the answer is (c).
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