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JEE Main 2013 (22 Apr, Shift 1) · Cells: EMF, Internal Resistance & Combinations

Cells: EMF, Internal Resistance & Combinations question from JEE Main 2013 (22 Apr, Shift 1)

Q42JEE Main 2013 · 22 APR · SHIFT 1Medium

Cells: EMF, Internal Resistance & Combinations

A dc source of emf $E_1 = 100$ V and internal resistance $r = 0.5\ \Omega$ , a storage battery of emf $E_2 = 90$ V and an external resistance R are connected as shown in figure. For what value of R no current will pass through the battery?

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Answer: (c)

No current in $E_2$ means voltage across $R$ equals $E_2 = 90\text{ V}$ .
Current from $E_1$ : $I = \frac{100 - 90}{0.5} = 20\text{ A}$ , all of which flows through $R$ .
$R = \frac{90}{20} = 4.5\ \Omega$ . So the answer is (c).

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