A deuteron and an alpha particle having equal kinetic energy enter perpendicularly into a magnetic field. Let rd and r α be their respective radii of circular path. The value of (rd)/(rα) is equal to: (a) 1 (b) 2 (c) √(2) (d) 1/√(2)

Answer: (c). Equal K: r ∝ √(m)/q. Deuteron: √(2)/1; alpha: √(4)/2 = 1. (rd)/(rα) = √(2) So the answer is (c) √(2).

A deuteron and an alpha particle having equal kinetic energy enter… | JEE Main 2021 (20 Jul, Shift 1)

Q69JEE Main 2021 · 20 JUL · SHIFT 1Medium

Moving Charge in a Magnetic Field

A deuteron and an alpha particle having equal kinetic energy enter perpendicularly into a magnetic field. Let rd and r $\alpha$ be their respective radii of circular path. The value of $\frac{r_d}{r_\alpha}$ is equal to:

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Answer: (c)

Equal $K$ : $r \propto \dfrac{\sqrt{m}}{q}$ .
Deuteron: $\dfrac{\sqrt{2}}{1}$ ; alpha: $\dfrac{\sqrt{4}}{2} = 1$ .
$\dfrac{r_d}{r_\alpha} = \sqrt{2}$
So the answer is (c) $\sqrt{2}$ .

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Moving Charge in a Magnetic Field question from JEE Main 2021 (20 Jul, Shift 1)

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