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JEE Main 2022 (27 Jun, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2022 (27 Jun, Shift 2)

Q160JEE Main 2022 · 27 JUN · SHIFT 2Easy

Thermodynamic Processes

A diatomic gas (γ\gamma = 1.4) does 400J of work when it is expanded isobarically. The heat given to the gas in the process is __________ J.

Numerical answer type. Work it out, then open the answer.

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Answer: 1400

  1. Isobaric: W=nRΔTW = nR\Delta T, Q=nCpΔTQ = nC_p\Delta T with Cp=γRγ−1C_p = \frac{\gamma R}{\gamma - 1}.
  2. QW=γγ−1=1.40.4=3.5\frac{Q}{W} = \frac{\gamma}{\gamma - 1} = \frac{1.4}{0.4} = 3.5
  3. Q=3.5×400=1400Q = 3.5 \times 400 = 1400 J
  4. Heat given =1400= 1400 J.
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