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MHT CET 2025 (20 Apr, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2025 (20 Apr, Shift 1)

Q83MHT CET 2025 · 20 APR · SHIFT 1Medium

Thermodynamic Processes

A diatomic gas (γ=75)\left(\gamma = \frac{7}{5}\right) is compressed adiabatically to volume V032\frac{V_0}{32}, where V0V_0 is its initial volume. The initial temperature of the gas is TiT_i in kelvin and the final temperature is xTixT_i in kelvin. The value of xx is

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Answer: (b)

  1. Adiabatic: T2=Ti(V1V2)γ−1T_2 = T_i\left(\frac{V_1}{V_2}\right)^{\gamma-1} with γ−1=25\gamma - 1 = \frac{2}{5}.
  2. T2=Ti⋅322/5=Ti⋅22=4TiT_2 = T_i \cdot 32^{2/5} = T_i \cdot 2^2 = 4T_i
  3. So the answer is (b) x=4x = 4.
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