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NEET 1996 (AIPMT) · Thermodynamic Processes

Thermodynamic Processes question from NEET 1996 (AIPMT)

Q252NEET 1996 · AIPMTMedium

Thermodynamic Processes

A diatomic gas initially at $18^\circ\text{C}$ is compressed adiabatically to one eighth of its original volume. The temperature after compression will be

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Answer: (a)

Diatomic: $\gamma = 1.4$ ; adiabatic $T_2 = T_1\left(\frac{V_1}{V_2}\right)^{0.4}$ , $T_1 = 291\ \text{K}$ .
$8^{0.4} = 2^{1.2} \approx 2.297$
$T_2 = 291 \times 2.297 \approx 668.4\ \text{K} = 395.4^\circ\text{C}$
So the answer is (a) $395.4^\circ\text{C}$ .

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