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JEE Main 2019 (12 Apr, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2019 (12 Apr, Shift 2)

Q214JEE Main 2019 · 12 APR · SHIFT 2Medium

Thermodynamic Processes

A diatomic gas with rigid molecules does 10 J of work when expanded at constant pressure. What would be the heat energy absorbed by the gas, in this process?

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Answer: (a)

Rigid diatomic: $C_p = \frac{7}{2}R$ ; at constant pressure $\frac{Q}{W} = \frac{C_p}{R} = \frac{7}{2}$ .
$Q = \frac{7}{2} \times 10 = 35\text{ J}$
So the answer is (a) 35 J.

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