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MHT CET 2024 (3 May, Shift 2) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2024 (3 May, Shift 2)

Q57MHT CET 2024 · 3 MAY · SHIFT 2Medium

Bohr Model: Orbits, Speed & Angular Momentum

A diatomic molecule has moment of inertia ' I ', By applying Bohr's quantization condition, its rotational energy in the nnth level is [n≥1][n \geq 1] [h= Planck's constant]

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Answer: (d)

  1. Quantisation: L=Iω=nh2πL = I\omega = \frac{nh}{2\pi}.
  2. E=L22I=n2h24π2⋅2I=n2(h28π2I)E = \frac{L^2}{2I} = \frac{n^2 h^2}{4\pi^2 \cdot 2I} = n^2\left(\frac{h^2}{8\pi^2 I}\right)
  3. So the answer is (d) n2(h28π2I)n^2\left(\frac{h^2}{8\pi^2 I}\right).
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