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JEE Main 2026 (4 Apr, Shift 2) · Special Purpose Diodes

Special Purpose Diodes question from JEE Main 2026 (4 Apr, Shift 2)

Q13JEE Main 2026 · 4 APR · SHIFT 2Medium

Special Purpose Diodes

A diode has Zener voltage of 10 V and maximum power dissipation of 0.5 W, then the minimum resistance to be used in series with this diode for safety when it is connected to a 25 V power supply is $\underline{\qquad\quad}\ \Omega$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 300

Maximum Zener current: $I = \frac{P}{V_Z} = \frac{0.5}{10} = 0.05$ A
Drop across series resistor: $25 - 10 = 15$ V
$R_{min} = \frac{15}{0.05} = 300\ \Omega$

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