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MHT CET 2023 (11 May, Shift 1) · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from MHT CET 2023 (11 May, Shift 1)

Q28MHT CET 2023 · 11 MAY · SHIFT 1Medium

Rotational Kinematics & Dynamics

A disc has mass $M$ and radius $R$ . How much tangential force should be applied to the rim of the disc, so as to rotate with angular velocity ' $\omega$ ' in time $t$ ?

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Answer: (b)

$\tau = FR = I\alpha$ with $I = \frac{1}{2}MR^2$ and $\alpha = \frac{\omega}{t}$ .
$FR = \frac{1}{2}MR^2\frac{\omega}{t}$
So the answer is (b) $F = \frac{MR\omega}{2t}$ .

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