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NEET 2001 (AIPMT) · Total Internal Reflection

Total Internal Reflection question from NEET 2001 (AIPMT)

Q62NEET 2001 · AIPMTMedium

Total Internal Reflection

A disc is placed on a surface of pond which has refractive index 5/3. A source of light is placed 4 m below the surface of liquid. The minimum radius of disc needed so that light is not coming out is,

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Answer: (b)

discsourcehRCairwater
  1. Light escapes only inside a circle where it meets the surface at less than CC: R=htan⁡C=hn2−1R = h\tan C = \frac{h}{\sqrt{n^2-1}}.
  2. n2−1=259−1=43\sqrt{n^2-1} = \sqrt{\frac{25}{9}-1} = \frac{4}{3}.
  3. R=44/3=3R = \frac{4}{4/3} = 3 m.
  4. So the answer is (b) 3 m.
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