Student Login

Home›Chapters›Rotational Motion PYQs›Rolling Motion›Question 12

MHT CET 2025 (20 Apr, Shift 2) · Rolling Motion

Rolling Motion question from MHT CET 2025 (20 Apr, Shift 2)

Q12MHT CET 2025 · 20 APR · SHIFT 2Easy

Rolling Motion

A disc of mass ' $m$ ' and radius ' $r$ ' rolls down an inclined plane of height ' $h$ '. When it reaches the bottom of the plane, its rotational kinetic energy is ( $g =$ acceleration due to gravity)

Show answer and solution

Answer: (a)

Total KE at the bottom $= mgh$ .
Disc: $\frac{K_{rot}}{K_{total}} = \frac{1/2}{1 + 1/2} = \frac{1}{3}$
$K_{rot} = \frac{mgh}{3}$
So the answer is (a) $\frac{mgh}{3}$ .

Report a mistake

More questions on Rolling Motion

An inclined plane makes an angle 30° with the horizontal. A solid sphere rolling down an…MHT CET 2025 (20 Apr, Shift 1)
A wheel is rolling on a plane surface. The speed of a particle on the highest point of…JEE Main 2025 (4 Apr, Shift 2)
A body slides down a smooth inclined plane of inclination θ and reaches the bottom with…MHT CET 2025 (19 Apr, Shift 2)
A solid sphere and a hollow sphere of the same mass and of same radius are rolled on an…JEE Main 2025 (24 Jan, Shift 2)
A solid sphere of mass ' m ' and radius ' r ' is allowed to roll without slipping from…JEE Main 2025 (23 Jan, Shift 1)
A circular ring and a solid sphere having same radius roll down on an inclined plane from…JEE Main 2025 (4 Apr, Shift 1)
A solid sphere rolling without friction on a horizontal surface with a constant speed of…MHT CET 2025 (20 Apr, Shift 2)
A force of 49 N acts tangentially at the highest point of a sphere (solid) of mass 20 kg…JEE Main 2025 (3 Apr, Shift 1)