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NEET 2019 · Rolling Motion

Rolling Motion question from NEET 2019

Q65NEET 2019Easy

Rolling Motion

A disc of radius 2 m and mass 100 kg rolls on a horizontal floor. Its centre of mass has speed of 20 cm/s. How much work is needed to stop it?

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Answer: (c)

  1. Work needed = total KE of the rolling disc.
  2. Disc: K=12mv2(1+12)=34mv2K = \frac{1}{2}mv^2\left(1 + \frac{1}{2}\right) = \frac{3}{4}mv^2
  3. K=34×100×(0.2)2=3K = \frac{3}{4}\times 100\times(0.2)^2 = 3 J
  4. So the answer is (c) 3 J.
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