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JEE Main 2026 (5 Apr, Shift 1) · Displacement Current, Maxwell's Equations & Production

Displacement Current, Maxwell's Equations & Production question from JEE Main 2026 (5 Apr, Shift 1)

Q2JEE Main 2026 · 5 APR · SHIFT 1Medium

Displacement Current, Maxwell's Equations & Production

A displacement current of 4.0 A can be set up in the space between two parallel plates of 6 μF6\ \mu\text{F} capacitor. The rate of change of potential difference across the plates of the capacitor is nearly α×106 V/s\alpha \times 10^{6}\text{ V/s}. The value of α\alpha is ______.

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Answer: (b)

  1. Displacement current Id=CdVdtI_d = C\dfrac{dV}{dt}.
  2. dVdt=4.06×10−6=0.67×106\dfrac{dV}{dt} = \dfrac{4.0}{6 \times 10^{-6}} = 0.67 \times 10^{6} V/s.
  3. So the answer is (b) α=0.67\alpha = 0.67.
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