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MHT CET 2022 (11 Aug, Shift 2) · Equilibrium, Third Law & Frames

Equilibrium, Third Law & Frames question from MHT CET 2022 (11 Aug, Shift 2)

Q12MHT CET 2022 · 11 AUG · SHIFT 2Easy

Equilibrium, Third Law & Frames

A door $1.2\text{ m}$ wide requires a force of $1\text{ N}$ to be applied perpendicular at the free end to open or close it. The perpendicular force required at a point $0.2\text{ m}$ distant from the hinges for opening or closing the door is

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Answer: (d)

The torque about the hinge must be the same: $F_1 r_1 = F_2 r_2$ .
$1 \times 1.2 = F \times 0.2$
$F = 6\text{ N}$
So the answer is (d) 6.0 N.

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