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Spherical Surfaces & Thin Lenses question from NEET 2019

Q90NEET 2019Medium

Spherical Surfaces & Thin Lenses

A double convex lens has focal length 25 cm. The radius of curvature of one of the surfaces is double of the other. Find the radii if the refractive index of the material of the lens is 1.5.

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Answer: (d)

  1. Radii RR and 2R2R: 125=0.5(1R+12R)=0.75R\frac{1}{25} = 0.5\left(\frac{1}{R} + \frac{1}{2R}\right) = \frac{0.75}{R}
  2. R=0.75×25=18.75R = 0.75 \times 25 = 18.75 cm, 2R=37.52R = 37.5 cm.
  3. So the answer is (d) 18.75 cm, 37.5 cm.
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