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JEE Main 2020 (6 Sep, Shift 2) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from JEE Main 2020 (6 Sep, Shift 2)

Q85JEE Main 2020 · 6 SEP · SHIFT 2Medium

Spherical Surfaces & Thin Lenses

A double convex lens has power P and same radii of curvature R of both the surfaces. The radius of curvature of a surface of a plano-convex lens made of the same material with power 1.5 P is:

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Answer: (a)

  1. Double convex: P=(μ−1)2RP = (\mu - 1)\frac{2}{R}.
  2. Plano-convex: 1.5P=(μ−1)1R′⇒(μ−1)1R′=(μ−1)3R1.5P = (\mu - 1)\frac{1}{R'} \Rightarrow (\mu - 1)\frac{1}{R'} = (\mu - 1)\frac{3}{R}
  3. So the answer is (a) R′=R3R' = \frac{R}{3}.
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