A double slit experiment is immersed in water of refractive index 1.33. The slit separationis 1 mm and the distance between slit and screen is 1.33 m. The slits are illuminated by a light of wavelength 6300. The fringewidth is (a) 4.9 × 10⁻⁴ m (b) 6.3 × 10⁻⁴ m (c) 8.6 × 10⁻⁴ m (d) 5.8 × 10⁻⁴ m

Answer: (b). In water β = (λ D)/(μ d). β = 6300×10⁻¹⁰×1.331.33×1×10⁻³ = 6.3×10⁻⁴ m So the answer is (b) 6.3×10⁻⁴ m.

A double slit experiment is immersed in water of refractive index… | MHT CET 2021 (21 Sep, Shift 1)

Q53MHT CET 2021 · 21 SEP · SHIFT 1Easy

YDSE: Film, Medium & Two Wavelengths

A double slit experiment is immersed in water of refractive index 1.33. The slit separationis 1 $\text{mm}$ and the distance between slit and screen is $1.33\text{ m}$ . The slits are illuminated by a light of wavelength $6300\ \text{\AA}$ . The fringewidth is

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Answer: (b)

In water $\beta = \frac{\lambda D}{\mu d}$ .
$\beta = \frac{6300\times10^{-10}\times1.33}{1.33\times1\times10^{-3}} = 6.3\times10^{-4}$ m
So the answer is (b) $6.3\times10^{-4}$ m.

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