A double slit experiment is immersed in water of refractive index 1.33. The slit separation is 1 mm, distance between slit and screen is 1.33 m The slits are illuminated by a light of wavelength 6300. The fringe width is (a) 4.9 × 10⁻⁴ m (b) 5.8 × 10⁻⁴ m (c) 6.3 × 10⁻⁴ m (d) 8.6 × 10⁻⁴ m

Answer: (c). In water β = (λ D)/(μ d). β = 6300×10⁻¹⁰×1.331.33×1×10⁻³ = 6.3×10⁻⁴ m So the answer is (c) 6.3×10⁻⁴ m.

A double slit experiment is immersed in water of refractive index… | MHT CET 2023 (11 May, Shift 1)

Q39MHT CET 2023 · 11 MAY · SHIFT 1Easy

YDSE: Film, Medium & Two Wavelengths

A double slit experiment is immersed in water of refractive index 1.33. The slit separation is $1\text{ mm}$ , distance between slit and screen is $1.33\text{ m}$ The slits are illuminated by a light of wavelength $6300\ \text{\AA}$ . The fringe width is

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Answer: (c)

In water $\beta = \frac{\lambda D}{\mu d}$ .
$\beta = \frac{6300\times10^{-10}\times1.33}{1.33\times1\times10^{-3}} = 6.3\times10^{-4}$ m
So the answer is (c) $6.3\times10^{-4}$ m.

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