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MHT CET 2026 (12 May, Shift 2) · YDSE: Film, Medium & Two Wavelengths

YDSE: Film, Medium & Two Wavelengths question from MHT CET 2026 (12 May, Shift 2)

Q3MHT CET 2026 · 12 MAY · SHIFT 2Easy

YDSE: Film, Medium & Two Wavelengths

A double slit experiment is immersed in water of refractive index $1.33$ . The slit separation is $1$ mm, distance between slit and screen is $1.33$ m. The slits are illuminated by a light of wavelength $6300$ \AA. The fringewidth is $x \times 10^{-4}\text{ m}$ . The value of $'x'$ is

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Answer: (d)

In water $\beta = \frac{\lambda D}{\mu d}$ .
$\beta = \frac{6300\times10^{-10}\times1.33}{1.33\times1\times10^{-3}} = 6.3\times10^{-4}$ m
So $x = 6.3$ , answer (d).

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