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MHT CET 2026 (15 Apr, Shift 2) · YDSE: Film, Medium & Two Wavelengths

YDSE: Film, Medium & Two Wavelengths question from MHT CET 2026 (15 Apr, Shift 2)

Q4MHT CET 2026 · 15 APR · SHIFT 2Easy

YDSE: Film, Medium & Two Wavelengths

A double slit experiment is immersed in water of refractive index $1.33$ . The slit separation is 1 mm, distance between slit and screen is $1.33$ m. The slits are illuminated by light of wavelength 6300 \AA. The fringe width is

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Answer: (b)

In water $\beta = \frac{\lambda D}{\mu d}$ .
$\beta = \frac{6300\times10^{-10}\times1.33}{1.33\times1\times10^{-3}} = 6.3\times10^{-4}$ m
So the answer is (b) $6.3\times10^{-4}$ m.

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