A driver applies the brakes on seeing the red traffic signal 400 m ahead. At the time of applying the brakes, the vehicle was moving with 15 m/s and retarding at 0.3 m/s². The distance covered by the vehicle from the traffic light 1 minute after the application of brakes is (a) 25 m (b) 360 m (c) 40 m (d) 375 m

Answer: (a). Time to stop = 15/0.3 = 50 s < 60 s, so the vehicle has stopped. Stopping distance = (15²)/(2 × 0.3) = 375 m Distance from the light = 400 - 375 = 25 m So the answer is (a) 25 m.

A driver applies the brakes on seeing the red traffic signal 400 m… | MHT CET 2021 (22 Sep, Shift 2)

Q27MHT CET 2021 · 22 SEP · SHIFT 2Medium

Equations of Kinematics

A driver applies the brakes on seeing the red traffic signal $400\text{ m}$ ahead. At the time of applying the brakes, the vehicle was moving with $15\text{ m/s}$ and retarding at $0.3\text{ m/s}^2$ . The distance covered by the vehicle from the traffic light 1 minute after the application of brakes is

Show answer and solution

Answer: (a)

Time to stop $= \frac{15}{0.3} = 50\text{ s} < 60\text{ s}$ , so the vehicle has stopped.
Stopping distance $= \frac{15^2}{2 \times 0.3} = 375\text{ m}$
Distance from the light $= 400 - 375 = 25\text{ m}$
So the answer is (a) 25 m.

Report a mistake

Equations of Kinematics question from MHT CET 2021 (22 Sep, Shift 2)

More questions on Equations of Kinematics