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JEE Main 2023 (30 Jan, Shift 2) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from JEE Main 2023 (30 Jan, Shift 2)

Q36JEE Main 2023 · 30 JAN · SHIFT 2Medium

Thermometry & Thermal Expansion

A faulty thermometer reads 5∘C5^\circ\text{C} in melting ice and 95∘C95^\circ\text{C} in steam. The correct temperature on absolute scale will be __________ K\text{K} when the faulty thermometer reads 41∘C41^\circ\text{C}.

Numerical answer type. Work it out, then open the answer.

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Answer: 313

  1. C100=x−595−5\frac{C}{100}=\frac{x-5}{95-5}
  2. C=41−590×100=40∘C=\frac{41-5}{90}\times100=40^\circC
  3. T=40+273=313T=40+273=313 K
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