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JEE Main 2025 (4 Apr, Shift 2) · Reflection & Mirrors

Reflection & Mirrors question from JEE Main 2025 (4 Apr, Shift 2)

Q14JEE Main 2025 · 4 APR · SHIFT 2Difficult

Reflection & Mirrors

A finite size object is placed normal to the principal axis at a distance of 30 cm from a convex mirror of focal length 30 cm. A plane mirror is now placed in such a way that the image produced by both the mirrors coincide with each other. The distance between the two mirrors is:

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Answer: (d)

  1. Convex mirror, f=+30f = +30, u=−30u = -30: 1v=130+130⇒v=+15 cm\frac{1}{v} = \frac{1}{30} + \frac{1}{30} \Rightarrow v = +15\text{ cm} (behind the mirror).
  2. Object to this image: 30+15=45 cm30 + 15 = 45\text{ cm}.
  3. A plane mirror forms its image as far behind as the object is in front, so it must sit midway: 22.522.5 cm from the object.
  4. Distance between mirrors =30−22.5=7.5 cm= 30 - 22.5 = 7.5\text{ cm}. So the answer is (d) 7.5 cm.
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