A flask contains Hydrogen and Argon in the ratio 2: 1 by mass. The temperature of the mixture is 30. The ratio of average kinetic energy per molecule of the two gases ( K argon/K hydrogen) is: (Given: Atomic Weight of Ar = 39.9) (a) 39.9/2 (b) 2 (c) 39.9 (d) 1

Answer: (d). Average translational KE per molecule = 3/2kBT depends only on temperature, not on mass or amount of gas. Both gases in the mixture are at the same T, so KAr/KH = 1. So the answer is (d) 1.

A flask contains Hydrogen and Argon in the ratio 2: 1 by mass. The… | JEE Main 2023 (15 Apr, Shift 1)

Q20JEE Main 2023 · 15 APR · SHIFT 1Easy

Pressure & Kinetic Energy of a Gas

A flask contains Hydrogen and Argon in the ratio $2 : 1$ by mass. The temperature of the mixture is $30^\circ\text{C}$ . The ratio of average kinetic energy per molecule of the two gases ( $K$ argon/K hydrogen) is: (Given: Atomic Weight of $\text{Ar} = 39.9$ )

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Answer: (d)

Average translational KE per molecule $= \frac{3}{2}k_BT$ depends only on temperature, not on mass or amount of gas.
Both gases in the mixture are at the same $T$ , so $K_{Ar}/K_{H} = 1$ .
So the answer is (d) 1.

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